AngularJS - Carica file
Stiamo fornendo un esempio di Upload File. Per sviluppare questa app, abbiamo utilizzato HTML, CSS e AngularJS. L'esempio seguente mostra come caricare il file utilizzando AngularJS.
<html>
<head>
<script src = "https://ajax.googleapis.com/ajax/libs/angularjs/1.3.14/angular.min.js">
</script>
</head>
<body ng-app = "myApp">
<div ng-controller = "myCtrl">
<input type = "file" file-model = "myFile"/>
<button ng-click = "uploadFile()">upload me</button>
</div>
<script>
var myApp = angular.module('myApp', []);
myApp.directive('fileModel', ['$parse', function ($parse) {
return {
restrict: 'A',
link: function(scope, element, attrs) {
var model = $parse(attrs.fileModel);
var modelSetter = model.assign;
element.bind('change', function() {
scope.$apply(function() {
modelSetter(scope, element[0].files[0]);
});
});
}
};
}]);
myApp.service('fileUpload', ['$https:', function ($https:) {
this.uploadFileToUrl = function(file, uploadUrl) {
var fd = new FormData();
fd.append('file', file);
$https:.post(uploadUrl, fd, {
transformRequest: angular.identity,
headers: {'Content-Type': undefined}
})
.success(function() {
})
.error(function() {
});
}
}]);
myApp.controller('myCtrl', ['$scope', 'fileUpload', function($scope, fileUpload) {
$scope.uploadFile = function() {
var file = $scope.myFile;
console.log('file is ' );
console.dir(file);
var uploadUrl = "/fileUpload";
fileUpload.uploadFileToUrl(file, uploadUrl);
};
}]);
</script>
</body>
</html>Risultato
Apri il file di codice salvato sopra in un browser web. Guarda il risultato.