パワーエレクトロニクス-インバーターの解決例

単相ハーフブリッジインバータの抵抗は2.5Ω、入力DC電圧は50Vです。以下を計算します-

Solution

a. The RMS voltage occurring at the fundamental frequency

$ E_ {1RMS} = 0.9 \ times 50V = 45V $

b. The power Output

RMS出力電圧$ E_ {ORMS} = E = 50V $

出力電力$ = E ^ {2} / R = \ left(50 \ right)^ {2} /2.5=1000W$

c. Peak current and average current

ピーク電流$ I_ {p} = E_ {0} / R = 50 / 2.5 = 20A $

平均電流$ = I_ {p} / 2 = 20/2 = 10A $

d. Harmonic RMS voltage

$ E_ {n} = \ left \ {\ left(E_ {ORMS} \ right)^ {2}-\ left(E_ {1RMS} \ right)^ {2} \ right \} ^ {0.5} = \ left [50 ^ {2} -45 ^ {2} \ right] ^ {0.5} = 21.8V $

e. Total harmonic distortion

$ E_ {n} / E_ {1RMS} = 21.8 / 45 = 0.48 \ times 100 \%= 48 \%$