Aptitude - Przykłady kwadratów i kostek

P 1 - √ 2025 =?

A - 45

B - 35

C - 34

D - 30

Answer - A

Explanation

Resolve 2025 into prime numbers first.
2025 = 5 x 5 x 3 x 3 x 3 x 3 = 52 x 32 x 32
∴ √2025 = 5 x 3 x 3 = 45

Q 2 - √ 54 x √ 6 =?

A - 24

B - 15

C - 18

D - 13

Answer - C

Explanation

√ 54 x √ 6 = √ 54 x 6 = √ (3 x 3 x 6 x 6)
= √ (32 x 62)
= √ 18

Q 3 - √ (248 + √ (51 + √169)) =?

A - 15

B - 12

C - 13

D - 16

Answer - D

Explanation

√(248 + √(51 + √169)) = √(248 + √(51 + 13))
= √(248 + √(64)) = √(248 + 8) = √(256) = 16

P 4 - √ (25/16) =?

A - 3/4

B - 5/4

C - 4

D - 4/5

Answer - B

Explanation

√(25/16) = √25/ √ 16 = 5/4.

Pytanie 5 - Jeśli √15 = 3,88. Co to jest √ (5/3)?

A - 1,213

B - 1,293

C - 1,321

D - 1,432

Answer - B

Explanation

√(5/3) = (√5 / √ 3) x (√3 / √ 3) =  √15 / 3 = 3.88/ 3 = 1.293

Q 6 - Jeśli √ 1369 = 37, to ile wynosi √13,69 + √0,1369 + √ 0,001369 + √ 0,00001369?

A - 4,0021

B - 4,1107

C - 3,1232

D - 2,1323

Answer - B

Explanation

√13.69 + √0.1369 + √ 0.001369 + √ 0.00001369 
= √(1369 / 100) + √(1369/ 10000) + √(1369/ 1000000) + √(1369/ 100000000)
= √1369 / √100 + √1369 / √10000 + √1369 / √1000000 + √1369 / √100000000
= 37/10 + 37/100 + 37/1000 + 37/ 10000 
= 3.7 + 0.37 + 0.037 + 0.0037 
 = 4.1107

P 7 - Jeśli √ 15 = 3,8729, to ile wynosi (√5 + √3) / (√5 - √3)?

A - 7,8729

B - 6,8729

C - 5,8729

D - 4,8729

Answer - A

Explanation

(√5 + √3)/(√5 - √3) 
= (√5 + √3)/(√5 - √3) * (√5 + √3)/(√5 + √3)
= (√5 + √3)2/(5 - 3)
= (5 + 3 + 2√5 + √3)/2 
= (8 + 2√15)/2
= 2(4 + √15)/2
= 4 + √15
= 4 + 3.8729
= 7.8729

Pytanie 8 - ∛9261 =?

A - 21

B - 17

C - 29

D - 23

Answer - A

Explanation

9261 = 3 x 3 x 3 x 7 x 7 x 7
= 33 x 73
∴ ∛9261 = (33 x 73)1/3
= 3 x 7 = 21.

P 9 - Jaka jest najmniejsza liczba wymagana do pomnożenia do 9720, aby utworzyć perfekcyjną kostkę?

A - 55

B - 65

C - 75

D - 85

Answer - C

Explanation

9261 = 2 x 2 x 2 x 3 x 3 x 3 x 5 x 3 x 3
= 23 x 33 x 32 x 5
∴ required no: 3 x 52 = 3 x 25 = 75