TikZ: Perluas stroke
Nov 29 2020
Saya mencoba menggambar beberapa spiral dan menanyakan pertanyaan ini beberapa hari yang lalu. The jawaban dengan hpekristiansen besar dan membantu banyak tapi karena tidak jelas apakah spiral adalah kanan atau kiri-tangan dengan melihat gambar, terlihat agak aneh dalam konteks saya yang diinginkan. Hari ini, hpekristiansen mengajukan pertanyaan sendiri tentang topik ini dan mendapat jawaban yang sangat membantu dari TikZling . Saya terutama menyukai jawaban menggunakan \foreachloop untuk menggambar segmen individu. Masalah yang tersisa adalah saya tidak dapat menggunakan doubleopsi jalur karena akan terlihat pada latar belakang non-putih, atau seperti dalam kasus penggunaan saya batang yang mengelilingi spiral.
Solusi untuk masalah ini adalah memotong jalur ganjil (mulai dari yang ketiga) di mana mereka berpotongan dengan jalur genap. Sayangnya, \path [clip]in Ti k Z tidak hanya menggunakan pusat jalur untuk memotong sesuatu dan tidak memiliki opsi untuk mengatur lebar garis yang akan dipotong sama sekali. Oleh karena itu saya bertanya-tanya apakah mungkin untuk memperluas jalur lebar garis yang diberikan ke bentuk seperti mungkin dengan perangkat lunak grafik vektor seperti Adobe Illustrator atau Affinity Designer.
Saat menggambar spiral dalam beberapa bagian (bagian kiri loop dan bagian kanan loop), ini akan memungkinkan penggunaan kode yang mirip dengan contoh berikut:
\documentclass[tikz]{standalone}
\begin{document}
\begin{tikzpicture}[even odd rule]
\newcommand{\radiusX}{0.7}
\newcommand{\radiusY}{1.5}
\newcommand{\strokeWidth}{0.1}
\newcommand{\strokeWidthExtra}{0.1}
\newcommand{\background}{({-\radiusX-1},-1) rectangle ({8+\radiusX+1},{2*\radiusY+1})}
\newcommand{\leftArc}{
(0.5, 0)
-- (0, 0)
arc (-90:-270:{\radiusX} and {\radiusY})
-- ++(0, -\strokeWidth)
arc (90:270:{\radiusX-\strokeWidth} and {\radiusY-\strokeWidth})
-- ++(0.5,0)
-- ++(0,-\strokeWidth)
-- cycle
}
\newcommand{\leftArcBig}{
({0.5+\strokeWidthExtra}, -\strokeWidthExtra)
-- ++({-0.5-\strokeWidthExtra}, 0)
arc (-90:-270:{\radiusX+\strokeWidthExtra} and {\radiusY+\strokeWidthExtra})
-- ++(0, {-\strokeWidth-2*\strokeWidthExtra})
arc (90:270:{\radiusX-\strokeWidth-\strokeWidthExtra} and {\radiusY-\strokeWidth-\strokeWidthExtra})
-- ++({0.5+\strokeWidthExtra},0)
-- ++(0,{-\strokeWidth+2*\strokeWidthExtra})
-- cycle
}
\newcommand{\rightArc}{
(-0.5,0)
-- (0,0)
arc (-90:90:{\radiusX} and {\radiusY})
-- ++(0,-\strokeWidth)
arc (90:-90:{\radiusX-\strokeWidth} and {\radiusY-\strokeWidth})
-- ++(-0.5,0)
-- ++(0,-{\strokeWidth})
-- cycle
}
\newcommand{\rightArcBig}{
(-{0.5-\strokeWidthExtra},-{\strokeWidthExtra})
-- ++({0.5+\strokeWidthExtra},0)
arc (-90:90:{\radiusX+\strokeWidthExtra} and {\radiusY+\strokeWidthExtra})
-- ++(0,{-\strokeWidth-2*\strokeWidthExtra})
arc (90:-90:{\radiusX-\strokeWidth-\strokeWidthExtra} and {\radiusY-\strokeWidth-\strokeWidthExtra})
-- ++({-0.5-\strokeWidthExtra},0)
-- ++(0,{-\strokeWidth-2*\strokeWidthExtra})
-- cycle
}
\shade[clip, top color = gray, bottom color = lightgray] \background;
\begin{scope}
\fill [black] \rightArc;
\clip \rightArcBig \background;
\fill [black] \leftArc;
\end{scope}
\begin{scope}[xshift = 2cm]
\fill [yellow] \rightArc;
\fill [yellow, fill opacity = 0.3] \rightArcBig;
\fill [red] \leftArc;
\fill [red, fill opacity = 0.3] \leftArcBig;
\end{scope}
\begin{scope}[xshift = 6cm]
\fill [black] \leftArc;
\clip \leftArcBig \background;
\fill [black] \rightArc;
\end{scope}
\begin{scope}[xshift = 8cm]
\fill [yellow] \leftArc;
\fill [yellow, fill opacity = 0.3] \leftArcBig;
\fill [red] \rightArc;
\fill [red, fill opacity = 0.3] \rightArcBig;
\end{scope}
\end{tikzpicture}
\end{document}
Jawaban
4 Noname Nov 29 2020 at 10:21
Bukan jawaban yang sebenarnya. Anda menanyakan apakah ada cara untuk membuat amplop jalur. Jawabannya adalah tidak ada cara bawaan atau sederhana untuk mencapai ini. Lebih buruk lagi, ada bukti analitik bahwa tidak ada cara yang sederhana dan umum . Untuk menghargai buktinya, ingatlah bahwa yang dapat dilakukan Ti k Z hanyalah membangun kurva Bezier. Perhatikan bahwa ini tidak memberi tahu Anda bahwa tidak ada cara yang tidak sesederhana itu. Faktanya, fakta bahwa MetaPost dan kawan-kawan memiliki rutinitas untuk itu memberi tahu Anda bahwa hal itu pada prinsipnya mungkin.
Alat lain yang mampu melakukan itu adalah penampil. Oke, biarkan pemirsa melakukan pekerjaan kotor. Ini memungkinkan seseorang untuk memecahkan masalah dengan cara lain, yang secara konseptual sama dengan posting ini : fadings. Sangat tidak nyaman, setidaknya bukan implementasi berikut, namun bukti prinsip. Pada dasarnya Anda dapat mengubah tingkat abu-abu menjadi transparansi, dan dengan demikian membuat garis hitam atau putih menjadi transparan. Objek ini dapat diletakkan di atas latar belakang yang sewenang-wenang. (Apakah saya sudah menyebutkan bahwa penerapan ini tidak nyaman?)
\documentclass{standalone}
\usepackage{tikz}
\usetikzlibrary{decorations.pathreplacing,fadings}%
\begin{document}
\begin{tikzfadingfrompicture}[name=custom fade]%
\tikzset{path decomposition/.style={%
postaction={decoration={show path construction,
lineto code={
\draw[#1] (\tikzinputsegmentfirst) -- (\tikzinputsegmentlast);
},
curveto code={
\draw[#1] (\tikzinputsegmentfirst) .. controls
(\tikzinputsegmentsupporta) and (\tikzinputsegmentsupportb)
..(\tikzinputsegmentlast) ;
},
closepath code={
\draw[#1] (\tikzinputsegmentfirst) -- (\tikzinputsegmentlast) {closepath};} }
,decorate}},
cv/.style={black, double=white,line width=0.6mm,double distance=1.2mm}}
\draw[cv,samples=201,domain=-2*pi:2*pi,smooth,
path decomposition={cv,shorten <=-0.05pt,shorten >=-0.05pt}]
plot (\x, {cos(10*\x r)} , {sin(10*\x r)} );
\end{tikzfadingfrompicture}%
\begin{tikzpicture}
\shade[clip, top color = gray!50!black, bottom color = gray!10]
(0,-2) rectangle (6,2);
\path[path fading=custom fade,fit fading=false,
fill=black] (0,-2) rectangle (8,2);
\end{tikzpicture}
\end{document}
4 AndrewStacey Nov 29 2020 at 22:56
Secara kebetulan, saya telah mengerjakan beberapa kode yang mungkin bisa membantu Anda. Ini dirancang untuk membagi jalur di titik persimpangan.
Ini didasarkan pada pustaka saya spath3( ctan dan github ) yang menyediakan struktur untuk memanipulasi jalur setelah mereka telah ditentukan tetapi sebelum mereka telah diperbaiki.
Ini jelas merupakan kode eksperimental dan dapat berubah, tetapi akan berguna untuk mendapatkan umpan balik, apakah itu masuk akal dan apa yang akan membuatnya berguna.
\documentclass{article}
\usepackage{xparse}
\usepackage{tikz}
\usepackage{spath3}
\usetikzlibrary{intersections,hobby,patterns}
\ExplSyntaxOn
\tikzset{
append~ spath/.code={
\spath_get_current_path:n {current path}
\spath_append:nn { current path } { #1 }
\spath_set_current_path:n { current path }
},
set~ spath/.code={
\spath_set_current_path:n { #1 }
\spath_get:nnN {#1} {final point} \l__spath_tmpa_tl
\tl_set:Nx \l__spath_tmpa_tl
{
\exp_not:c {tikz@lastx}=\tl_item:Nn \l__spath_tmpa_tl {1}
\exp_not:c {tikz@lasty}=\tl_item:Nn \l__spath_tmpa_tl {2}
\exp_not:c {tikz@lastxsaved}=\tl_item:Nn \l__spath_tmpa_tl {1}
\exp_not:c {tikz@lastysaved}=\tl_item:Nn \l__spath_tmpa_tl {2}
}
\tl_use:N \l__spath_tmpa_tl
},
shorten~spath~at~end/.code~ 2~ args={
\spath_shorten:nn {#1} {#2}
},
shorten~spath~at~start/.code~ 2~ args ={
\spath_reverse:n {#1}
\spath_shorten:nn {#1} {#2}
\spath_reverse:n {#1}
},
shorten~spath~both~ends/.code~ 2~ args={
\spath_shorten:nn {#1} {#2}
\spath_reverse:n {#1}
\spath_shorten:nn {#1} {#2}
\spath_reverse:n {#1}
},
globalise~ spath/.code={
\spath_globalise:n {#1}
},
translate~ spath/.code~ n~ args={3}{
\spath_translate:nnn {#1}{#2}{#3}
},
split~ at~ self~ intersections/.code~ 2~ args={
\use:c {tikz@addmode}{
\group_begin:
\spath_get_current_path:n {spath split tmpa}
\spath_split_at_self_intersections:nnn {spath split tmpa} {#1} {#2}
\group_end:
}
},
split~ at~ intersections/.code~ n~ args={5}{
\spath_split_at_intersections:nnnnn {#1}{#2}{#3}{#4}{#5}
}
}
\tl_new:N \l__spath_shorten_fa_tl
\tl_new:N \l__spath_shorten_path_tl
\tl_new:N \l__spath_shorten_last_tl
\int_new:N \l__spath_shorten_int
\fp_new:N \l__spath_shorten_x_fp
\fp_new:N \l__spath_shorten_y_fp
\cs_new_nopar:Npn \spath_shorten:nn #1#2
{
\group_begin:
\spath_get:nnN {#1} {final action} \l__spath_shorten_fa_tl
\spath_get:nnN {#1} {path} \l__spath_shorten_path_tl
\tl_reverse:N \l__spath_shorten_path_tl
\tl_clear:N \l__spath_shorten_last_tl
\tl_if_eq:NNTF \l__spath_shorten_fa_tl \g__spath_curveto_tl
{
\int_set:Nn \l__spath_shorten_int {3}
}
{
\int_set:Nn \l__spath_shorten_int {1}
}
\prg_replicate:nn { \l__spath_shorten_int }
{
\tl_put_right:Nx \l__spath_shorten_last_tl
{
{\tl_head:N \l__spath_shorten_path_tl}
}
\tl_set:Nx \l__spath_shorten_path_tl {\tl_tail:N \l__spath_shorten_path_tl}
\tl_put_right:Nx \l__spath_shorten_last_tl
{
{\tl_head:N \l__spath_shorten_path_tl}
}
\tl_set:Nx \l__spath_shorten_path_tl {\tl_tail:N \l__spath_shorten_path_tl}
\tl_put_right:Nx \l__spath_shorten_last_tl
{
\tl_head:N \l__spath_shorten_path_tl
}
\tl_set:Nx \l__spath_shorten_path_tl {\tl_tail:N \l__spath_shorten_path_tl}
}
\tl_put_right:Nx \l__spath_shorten_last_tl
{
{\tl_item:Nn \l__spath_shorten_path_tl {1}}
{\tl_item:Nn \l__spath_shorten_path_tl {2}}
}
\tl_put_right:NV \l__spath_shorten_last_tl \g__spath_moveto_tl
\tl_reverse:N \l__spath_shorten_path_tl
\fp_set:Nn \l__spath_shorten_x_fp
{
\dim_to_fp:n {\tl_item:Nn \l__spath_shorten_last_tl {4}}
-
\dim_to_fp:n {\tl_item:Nn \l__spath_shorten_last_tl {1}}
}
\fp_set:Nn \l__spath_shorten_y_fp
{
\dim_to_fp:n {\tl_item:Nn \l__spath_shorten_last_tl {5}}
-
\dim_to_fp:n {\tl_item:Nn \l__spath_shorten_last_tl {2}}
}
\fp_set:Nn \l__spath_shorten_len_fp
{
sqrt( \l__spath_shorten_x_fp * \l__spath_shorten_x_fp + \l__spath_shorten_y_fp * \l__spath_shorten_y_fp )
}
\fp_set:Nn \l__spath_shorten_len_fp
{
(\l__spath_shorten_len_fp - #2)/ \l__spath_shorten_len_fp
}
\tl_reverse:N \l__spath_shorten_last_tl
\tl_if_eq:NNTF \l__spath_shorten_fa_tl \g__spath_curveto_tl
{
\fp_set:Nn \l__spath_shorten_len_fp
{
1 - (1 -\l__spath_shorten_len_fp)/3
}
\spath_split_curve:VVNN \l__spath_shorten_len_fp \l__spath_shorten_last_tl
\l__spath_shorten_lasta_tl
\l__spath_shorten_lastb_tl
}
{
\spath_split_line:VVNN \l__spath_shorten_len_fp \l__spath_shorten_last_tl
\l__spath_shorten_lasta_tl
\l__spath_shorten_lastb_tl
}
\prg_replicate:nn {3}
{
\tl_set:Nx \l__spath_shorten_lasta_tl {\tl_tail:N \l__spath_shorten_lasta_tl}
}
\tl_put_right:NV \l__spath_shorten_path_tl \l__spath_shorten_lasta_tl
\tl_gset_eq:NN \l__spath_smuggle_tl \l__spath_shorten_path_tl
\group_end:
\spath_clear:n {#1}
\spath_put:nnV {#1} {path} \l__spath_smuggle_tl
}
\cs_generate_variant:Nn \spath_shorten:nn {Vn, VV}
\cs_generate_variant:Nn \spath_reverse:n {V}
\cs_generate_variant:Nn \spath_append_no_move:nn {VV}
\cs_generate_variant:Nn \spath_prepend_no_move:nn {VV}
\cs_new_nopar:Npn \spath_intersect:nn #1#2
{
\spath_get:nnN {#1} {path} \l__spath_tmpa_tl
\spath_get:nnN {#2} {path} \l__spath_tmpb_tl
\pgfintersectionofpaths%
{%
\pgfsetpath\l__spath_tmpa_tl
}{%
\pgfsetpath\l__spath_tmpb_tl
}
}
\cs_generate_variant:Nn \spath_intersect:nn {VV, Vn}
\cs_new_nopar:Npn \spath_split_line:nnNN #1#2#3#4
{
\group_begin:
\tl_gclear:N \l__spath_smuggle_tl
\tl_set_eq:NN \l__spath_tmpa_tl \g__spath_moveto_tl
\tl_put_right:Nx \l__spath_tmpa_tl {
{\tl_item:nn {#2} {2}}
{\tl_item:nn {#2} {3}}
}
\tl_put_right:NV \l__spath_tmpa_tl \g__spath_lineto_tl
\tl_put_right:Nx \l__spath_tmpa_tl
{
{\fp_to_dim:n
{
(1 - #1) * \tl_item:nn {#2} {2} + (#1) * \tl_item:nn {#2} {5}
}}
{\fp_to_dim:n
{
(1 - #1) * \tl_item:nn {#2} {3} + (#1) * \tl_item:nn {#2} {6}
}}
}
\tl_gset_eq:NN \l__spath_smuggle_tl \l__spath_tmpa_tl
\group_end:
\tl_set_eq:NN #3 \l__spath_smuggle_tl
\group_begin:
\tl_gclear:N \l__spath_smuggle_tl
\tl_set_eq:NN \l__spath_tmpa_tl \g__spath_moveto_tl
\tl_put_right:Nx \l__spath_tmpa_tl
{
{\fp_to_dim:n
{
(1 - #1) * \tl_item:nn {#2} {2} + (#1) * \tl_item:nn {#2} {5}
}}
{\fp_to_dim:n
{
(1 - #1) * \tl_item:nn {#2} {3} + (#1) * \tl_item:nn {#2} {6}
}}
}
\tl_put_right:NV \l__spath_tmpa_tl \g__spath_lineto_tl
\tl_put_right:Nx \l__spath_tmpa_tl {
{\tl_item:nn {#2} {5}}
{\tl_item:nn {#2} {6}}
}
\tl_gset_eq:NN \l__spath_smuggle_tl \l__spath_tmpa_tl
\group_end:
\tl_set_eq:NN #4 \l__spath_smuggle_tl
}
\cs_generate_variant:Nn \spath_split_line:nnNN {nVNN, VVNN}
\int_new:N \l__spath_split_int
\int_new:N \l__spath_splitat_int
\fp_new:N \l__spath_split_fp
\bool_new:N \l__spath_split_bool
\tl_new:N \l__spath_split_path_tl
\tl_new:N \l__spath_split_patha_tl
\tl_new:N \l__spath_split_pathb_tl
\tl_new:N \l__spath_split_intoa_tl
\tl_new:N \l__spath_split_intob_tl
\dim_new:N \l__spath_splitx_dim
\dim_new:N \l__spath_splity_dim
\cs_new_nopar:Npn \spath_split_at:nnnn #1#2#3#4
{
\group_begin:
\int_set:Nn \l__spath_splitat_int {\fp_to_int:n {floor(#2) + 1}}
\fp_set:Nn \l__spath_split_fp {#2 - floor(#2)}
\int_zero:N \l__spath_split_int
\bool_set_true:N \l__spath_split_bool
\spath_get:nnN {#1} {path} \l__spath_split_path_tl
\tl_clear:N \l__spath_split_patha_tl
\dim_zero:N \l__spath_splitx_dim
\dim_zero:N \l__spath_splity_dim
\bool_until_do:nn {
\tl_if_empty_p:N \l__spath_split_path_tl
||
\int_compare_p:n { \l__spath_splitat_int == \l__spath_split_int }
}
{
\tl_set:Nx \l__spath_tmpc_tl {\tl_head:N \l__spath_split_path_tl}
\tl_set:Nx \l__spath_split_path_tl {\tl_tail:N \l__spath_split_path_tl }
\tl_case:Nn \l__spath_tmpc_tl
{
\g__spath_lineto_tl
{
\int_incr:N \l__spath_split_int
}
\g__spath_curvetoa_tl
{
\int_incr:N \l__spath_split_int
}
}
\int_compare:nT { \l__spath_split_int < \l__spath_splitat_int }
{
\tl_put_right:NV \l__spath_split_patha_tl \l__spath_tmpc_tl
\tl_put_right:Nx \l__spath_split_patha_tl
{{ \tl_head:N \l__spath_split_path_tl }}
\dim_set:Nn \l__spath_splitx_dim {\tl_head:N \l__spath_split_path_tl}
\tl_set:Nx \l__spath_split_path_tl {\tl_tail:N \l__spath_split_path_tl }
\tl_put_right:Nx \l__spath_split_patha_tl
{{ \tl_head:N \l__spath_split_path_tl }}
\dim_set:Nn \l__spath_splity_dim {\tl_head:N \l__spath_split_path_tl}
\tl_set:Nx \l__spath_split_path_tl {\tl_tail:N \l__spath_split_path_tl }
}
}
\tl_clear:N \l__spath_split_pathb_tl
\tl_put_right:NV \l__spath_split_pathb_tl \g__spath_moveto_tl
\tl_put_right:Nx \l__spath_split_pathb_tl
{
{\dim_use:N \l__spath_splitx_dim}
{\dim_use:N \l__spath_splity_dim}
}
\tl_case:Nn \l__spath_tmpc_tl
{
\g__spath_lineto_tl
{
\tl_put_right:NV \l__spath_split_pathb_tl \l__spath_tmpc_tl
\tl_put_right:Nx \l__spath_split_pathb_tl
{{ \tl_head:N \l__spath_split_path_tl }}
\tl_set:Nx \l__spath_split_path_tl {\tl_tail:N \l__spath_split_path_tl }
\tl_put_right:Nx \l__spath_split_pathb_tl
{{ \tl_head:N \l__spath_split_path_tl }}
\tl_set:Nx \l__spath_split_path_tl {\tl_tail:N \l__spath_split_path_tl }
\spath_split_line:VVNN \l__spath_split_fp \l__spath_split_pathb_tl
\l__spath_split_intoa_tl
\l__spath_split_intob_tl
\prg_replicate:nn {3} {
\tl_set:Nx \l__spath_split_intoa_tl {\tl_tail:N \l__spath_split_intoa_tl}
}
\tl_put_right:NV \l__spath_split_patha_tl \l__spath_split_intoa_tl
\tl_put_right:NV \l__spath_split_intob_tl \l__spath_split_path_tl
}
\g__spath_curvetoa_tl
{
\tl_put_right:NV \l__spath_split_pathb_tl \l__spath_tmpc_tl
\tl_put_right:Nx \l__spath_split_pathb_tl
{{ \tl_head:N \l__spath_split_path_tl }}
\tl_set:Nx \l__spath_split_path_tl {\tl_tail:N \l__spath_split_path_tl }
\tl_put_right:Nx \l__spath_split_pathb_tl
{{ \tl_head:N \l__spath_split_path_tl }}
\tl_set:Nx \l__spath_split_path_tl {\tl_tail:N \l__spath_split_path_tl }
\prg_replicate:nn {2} {
\tl_put_right:Nx \l__spath_split_pathb_tl
{ \tl_head:N \l__spath_split_path_tl }
\tl_set:Nx \l__spath_split_path_tl {\tl_tail:N \l__spath_split_path_tl }
\tl_put_right:Nx \l__spath_split_pathb_tl
{{ \tl_head:N \l__spath_split_path_tl }}
\tl_set:Nx \l__spath_split_path_tl {\tl_tail:N \l__spath_split_path_tl }
\tl_put_right:Nx \l__spath_split_pathb_tl
{{ \tl_head:N \l__spath_split_path_tl }}
\tl_set:Nx \l__spath_split_path_tl {\tl_tail:N \l__spath_split_path_tl }
}
\spath_split_curve:VVNN \l__spath_split_fp \l__spath_split_pathb_tl
\l__spath_split_intoa_tl
\l__spath_split_intob_tl
\prg_replicate:nn {3} {
\tl_set:Nx \l__spath_split_intoa_tl {\tl_tail:N \l__spath_split_intoa_tl}
}
\tl_put_right:NV \l__spath_split_patha_tl \l__spath_split_intoa_tl
\tl_put_right:NV \l__spath_split_intob_tl \l__spath_split_path_tl
}
}
\spath_gclear_new:n {#3}
\spath_gput:nnV {#3} {path} \l__spath_split_patha_tl
\spath_gclear_new:n {#4}
\spath_gput:nnV {#4} {path} \l__spath_split_intob_tl
\group_end:
}
\cs_generate_variant:Nn \spath_split_at:nnnn {VVnn, Vnnn}
\cs_new_nopar:Npn \spath_explode_into_list:nn #1#2
{
\tl_clear_new:c {l__spath_list_#2}
\int_zero:N \l__spath_tmpa_int
\spath_map_segment_inline:nn {#1} {
\tl_if_eq:NNF ##1 \g__spath_moveto_tl
{
\spath_clear_new:n {#2 _ \int_use:N \l__spath_tmpa_int}
\spath_put:nnV {#2 _ \int_use:N \l__spath_tmpa_int} {path} ##2
\tl_put_right:cx {l__spath_list_#2} {{#2 _ \int_use:N \l__spath_tmpa_int}}
\int_incr:N \l__spath_tmpa_int
}
}
}
\tl_new:N \spathselfintersectioncount
\tl_new:N \l__spath_split_tmpa_tl
\tl_new:N \l__spath_split_path_a_tl
\tl_new:N \l__spath_split_path_b_tl
\tl_new:N \l__spath_split_join_a_tl
\tl_new:N \l__spath_split_join_b_tl
\tl_new:N \l__spath_split_first_tl
\tl_new:N \l__spath_split_second_tl
\tl_new:N \l__spath_split_one_tl
\tl_set:Nn \l__spath_split_one_tl {1}
\tl_new:N \l__spath_split_I_tl
\tl_set:Nn \l__spath_split_I_tl {I}
\int_new:N \l__spath_split_count_int
\int_new:N \l__spath_split_intersection_int
\seq_new:N \l__spath_split_segments_seq
\seq_new:N \l__spath_split_segments_processed_seq
\seq_new:N \l__spath_split_segments_middle_seq
\seq_new:N \l__spath_split_joins_seq
\seq_new:N \l__spath_split_joins_processed_seq
\seq_new:N \l__spath_split_joins_middle_seq
\seq_new:N \l__spath_split_intersections_seq
\bool_new:N \l__spath_split_join_bool
% We'll run this on each segment
%
% Arguments:
% 1. Path to split
% 2. Prefix for name of new paths
% 3. List of how to split at intersections
% A - don't split first path at intersection
% B - don't split second path at intersection
% C - split both paths at intersection
%
\cs_new_nopar:Npn \spath_split_at_self_intersections:nnn #1#2#3
{
\group_begin:
% The third argument says whether to rejoin segments at the intersections
\seq_set_split:Nnn \l__spath_split_intersections_seq {} {#3}
% Clone the path as we'll mess around with it
\spath_clone:nn {#1} {spath split tmp}
% Clear the sequence of joining information
% The join information says whether to rejoin a segment to its predecessor
\seq_clear:N \l__spath_split_joins_seq
% Check the last action to see if it is a close path
\spath_get:nnN {spath split tmp} {final action} \l__spath_split_tmpa_tl
\tl_if_eq:NNTF \l__spath_split_tmpa_tl \g__spath_closepath_tl
{
% Last action is a close, so mark it as needing rejoining
\seq_put_right:Nn \l__spath_split_joins_seq {1}
}
{
% Last action is not a close, so mark it as needing rejoining
\seq_put_right:Nn \l__spath_split_joins_seq {0}
}
% Remove close paths
\spath_open_path:n {spath split tmp}
% Separate into segments (creates a token list)
\spath_explode_into_list:nn {spath split tmp}{split segments}
% so convert to a sequence
\seq_set_split:NnV \l__spath_split_segments_seq {} \l__spath_list_splitsegments
% Iterate over the number of terms in the sequence, adding the
% rejoining information
\int_step_inline:nnnn {1} {1} {\seq_count:N \l__spath_split_segments_seq - 1}
{
\seq_put_right:Nn \l__spath_split_joins_seq {1}
}
% Clear a couple of auxiliaries
\seq_clear:N \l__spath_split_segments_processed_seq
\seq_clear:N \l__spath_split_joins_processed_seq
\int_zero:N \l__spath_split_count_int
\int_zero:N \l__spath_split_intersection_int
% Iterate over the sequence
\bool_while_do:nn
{
!\seq_if_empty_p:N \l__spath_split_segments_seq
}
{
% Remove the left-most items for consideration
\seq_pop_left:NN \l__spath_split_segments_seq \l__spath_split_path_a_tl
\seq_pop_left:NN \l__spath_split_joins_seq \l__spath_split_join_a_tl
% Clear some sequences, these will hold any pieces we create from splitting our path under consideration except for the first piece
\seq_clear:N \l__spath_split_segments_middle_seq
\seq_clear:N \l__spath_split_joins_middle_seq
% Put the rejoining information in the processed sequence
\seq_put_right:NV \l__spath_split_joins_processed_seq \l__spath_split_join_a_tl
% Iterate over the rest of the segments
\int_step_inline:nnnn {1} {1} {\seq_count:N \l__spath_split_segments_seq}
{
% Store the next segment for intersection
\tl_set:Nx \l__spath_split_path_b_tl {\seq_item:Nn \l__spath_split_segments_seq {##1}}
% Get the next joining information
\tl_set:Nx \l__spath_split_join_b_tl {\seq_item:Nn \l__spath_split_joins_seq {##1}}
% And put it onto our saved stack of joins
\seq_put_right:NV \l__spath_split_joins_middle_seq \l__spath_split_join_b_tl
% Sort intersections along the first path
\pgfintersectionsortbyfirstpath
% Find the intersections of these segments
\spath_intersect:VV \l__spath_split_path_a_tl \l__spath_split_path_b_tl
% If we get intersections
\int_compare:nTF {\pgfintersectionsolutions > 0}
{
% Find the times of the first intersection (which will be the first along the segment we're focussing on)
\pgfintersectiongetsolutiontimes{1}{\l__spath_split_first_tl}{\l__spath_split_second_tl}
% Ignore intersections that are very near end points
\bool_if:nT {
\fp_compare_p:n {
\l__spath_split_first_tl < .99
}
&&
\fp_compare_p:n {
\l__spath_split_first_tl > .01
}
&&
\fp_compare_p:n {
\l__spath_split_second_tl < .99
}
&&
\fp_compare_p:n {
\l__spath_split_second_tl > .01
}
}
{
% We have a genuine intersection
\int_incr:N \l__spath_split_intersection_int
}
% Do we split the first path?
\bool_if:nT {
\fp_compare_p:n {
\l__spath_split_first_tl < .99
}
&&
\fp_compare_p:n {
\l__spath_split_first_tl > .01
}
}
{
% Split the first path at the intersection
\spath_split_at:VVnn \l__spath_split_path_a_tl \l__spath_split_first_tl {split \int_use:N \l__spath_split_count_int}{split \int_eval:n { \l__spath_split_count_int + 1}}
% Put the latter part into our temporary sequence
\seq_put_left:Nx \l__spath_split_segments_middle_seq {split \int_eval:n{ \l__spath_split_count_int + 1}}
% Mark this intersection in the joining information
% Label the breaks as "IA#" and "IB#"
\seq_put_left:Nx \l__spath_split_joins_middle_seq {IA \int_use:N \l__spath_split_intersection_int }
% Replace our segment under consideration by the initial part
\tl_set:Nx \l__spath_split_path_a_tl {split \int_use:N \l__spath_split_count_int }
% Increment our counter
\int_incr:N \l__spath_split_count_int
\int_incr:N \l__spath_split_count_int
}
% Do we split the second path?
\bool_if:nTF {
\fp_compare_p:n {
\l__spath_split_second_tl < .99
}
&&
\fp_compare_p:n {
\l__spath_split_second_tl > .01
}
}
{
% Split the second segment at the intersection point
\spath_split_at:VVnn \l__spath_split_path_b_tl \l__spath_split_second_tl {split \int_use:N \l__spath_split_count_int}{split \int_eval:n { \l__spath_split_count_int + 1}}
% Add these segments to our list of segments we've considered
\seq_put_right:Nx \l__spath_split_segments_middle_seq {split \int_eval:n{ \l__spath_split_count_int}}
\seq_put_right:Nx \l__spath_split_segments_middle_seq {split \int_eval:n{ \l__spath_split_count_int + 1}}
\seq_put_right:Nx \l__spath_split_joins_middle_seq {IB \int_use:N \l__spath_split_intersection_int}
% Increment the counter
\int_incr:N \l__spath_split_count_int
\int_incr:N \l__spath_split_count_int
}
{
% If we didn't split the second segment, we just put the second segment on the list of segments we've considered
\seq_put_right:NV \l__spath_split_segments_middle_seq \l__spath_split_path_b_tl
}
}
{
% If we didn't split the second segment, we just put the second segment on the list of segments we've considered
\seq_put_right:NV \l__spath_split_segments_middle_seq \l__spath_split_path_b_tl
}
}
% Having been through the loop for our segment under consideration, we replace the segment list since some of them might have been split and add any remainders of the segment under consideration
\seq_set_eq:NN \l__spath_split_segments_seq \l__spath_split_segments_middle_seq
\seq_set_eq:NN \l__spath_split_joins_seq \l__spath_split_joins_middle_seq
% We add the initial segment to our sequence of dealt with segments
\seq_put_right:NV \l__spath_split_segments_processed_seq \l__spath_split_path_a_tl
}
\seq_clear:N \l__spath_split_segments_seq
\tl_set:Nx \l__spath_split_path_a_tl {\seq_item:Nn \l__spath_split_segments_processed_seq {1}}
\int_step_inline:nnnn {2} {1} {\seq_count:N \l__spath_split_segments_processed_seq}
{
% Get the next path and joining information
\tl_set:Nx \l__spath_split_path_b_tl {\seq_item:Nn \l__spath_split_segments_processed_seq {##1}}
\tl_set:Nx \l__spath_split_join_b_tl {\seq_item:Nn \l__spath_split_joins_processed_seq {##1}}
% Do we join this to our previous path?
\bool_set_false:N \l__spath_split_join_bool
% If it came from when we split the original path, join them
\tl_if_eq:NNT \l__spath_split_join_b_tl \l__spath_split_one_tl
{
\bool_set_true:N \l__spath_split_join_bool
}
% Is this a labelled intersection?
\tl_set:Nx \l__spath_split_tmpa_tl {\tl_head:N \l__spath_split_join_b_tl}
\tl_if_eq:NNT \l__spath_split_tmpa_tl \l__spath_split_I_tl
{
% Strip off the "I" prefix
\tl_set:Nx \l__spath_split_tmpa_tl {\tl_tail:N \l__spath_split_join_b_tl}
% Next letter is "A" or "B"
\tl_set:Nx \l__spath_split_join_b_tl {\tl_head:N \l__spath_split_tmpa_tl}
% Remainder is the intersection index
\int_compare:nTF {\tl_tail:N \l__spath_split_tmpa_tl <= \seq_count:N \l__spath_split_intersections_seq}
{
\tl_set:Nx \l__spath_split_join_a_tl {\seq_item:Nn \l__spath_split_intersections_seq {\tl_tail:N \l__spath_split_tmpa_tl}}
}
{
% Default is to rejoin neither segment
\tl_set:Nn \l__spath_split_join_a_tl {C}
}
\tl_if_eq:NNT \l__spath_split_join_a_tl \l__spath_split_join_b_tl
{
\bool_set_true:N \l__spath_split_join_bool
}
}
\bool_if:NTF \l__spath_split_join_bool
{
% Yes, so append it
\spath_append_no_move:VV \l__spath_split_path_a_tl \l__spath_split_path_b_tl
}
{
% No, so put the first path onto the stack
\seq_put_right:NV \l__spath_split_segments_seq \l__spath_split_path_a_tl
% Swap out the paths
\tl_set_eq:NN \l__spath_split_path_a_tl \l__spath_split_path_b_tl
}
}
% Do we need to add the first path to the last?
\tl_set:Nx \l__spath_split_join_a_tl {\seq_item:Nn \l__spath_split_joins_processed_seq {1}}
\tl_if_eq:NNTF \l__spath_split_join_a_tl \l__spath_split_one_tl
{
\tl_set:Nx \l__spath_split_path_b_tl {\seq_item:Nn \l__spath_split_segments_processed_seq {1}}
\spath_prepend_no_move:VV \l__spath_split_path_b_tl \l__spath_split_path_a_tl
}
{
\seq_put_right:NV \l__spath_split_segments_seq \l__spath_split_path_a_tl
}
% Put our paths into a list
\int_zero:N \l__spath_split_count_int
\seq_map_inline:Nn \l__spath_split_segments_seq
{
\int_incr:N \l__spath_split_count_int
\spath_gclone:nn {##1} {#2~\int_use:N \l__spath_split_count_int}
}
\tl_gset:NV \spathselfintersectioncount \l__spath_split_count_int
\group_end:
}
\ExplSyntaxOff
\begin{document}
\begin{tikzpicture}[use Hobby shortcut]
\shade[left color=cyan, right color=magenta, shading angle=90] (-.5,-.2) rectangle (7.5,2.2);
\fill[pattern=bricks, pattern color=white] (-.5,-.2) rectangle (7.5,2.2);
\path
[
split at self intersections={coil}{AAAAAAAAAAAAAAAA}
] ([out angle=0]0,0)
.. +(.85,1) .. +(.25,2) .. +(-.35,1) .. ++(.5,0)
.. +(.85,1) .. +(.25,2) .. +(-.35,1) .. ++(.5,0)
.. +(.85,1) .. +(.25,2) .. +(-.35,1) .. ++([in angle=180].5,0)
;
\foreach \k in {1,..., \spathselfintersectioncount} {
\tikzset{shorten spath both ends={coil \k}{2pt}, globalise spath=coil \k}
}
\foreach \k in {1,..., 4} {
\draw[set spath=coil \k];
}
\foreach[evaluate=\l as \xshift using \l*.5cm] \l in {0,...,10} {
\foreach \k in {5,..., 9} {
\draw[translate spath={coil \k}{\xshift pt}{0pt},set spath=coil \k];
}
}
\draw[translate spath={coil 10}{5cm}{0pt},set spath=coil 10];
\end{tikzpicture}
\end{document}
Jelas, sebagian besar dari itu pada akhirnya akan menemukan jalannya ke dalam spath3paket dan bagian kuncinya ada di tikzpicturebagian akhir. Apa yang dilakukannya adalah mengambil jalur dasar dan membaginya di tempat yang berpotongan sendiri. Ini kemudian mempersingkat bagian-bagian ini untuk membuat celah. Potongan-potongan ini kemudian dapat digunakan kembali (dengan terjemahan) untuk membuat koil. Hasilnya adalah gambar berikut, dengan latar belakang untuk menunjukkan bahwa tidak ada doubletipuan yang terjadi di sini.
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