Dart obtiene el elemento de pistas de String usando RegExp
Nov 28 2020
cuando recupero datos de la URL de nuestro sitio web, que devuelven esta salida en uno de los campos de la API de descanso y trato de encontrar si tracks
está contenida, obtengo la URL de la que en esta tracks
fuente a continuación es la que necesito obtener
String test = """
<div class=\"wp-playlist wp-audio-playlist wp-playlist-light\">\n
<div class=\"wp-playlist-current-item\"></div>\n
<p>\t\t<audio controls=\"controls\" preload=\"none\" width=\"\n\t\t\t\t1118\t\"\n\t\t>
</audio></p>\n<div class=\"wp-playlist-next\"></div>\n<div class=\"wp-playlist-prev\">
</div>\n<p>\t<noscript></p>\n<ol>\n<li>
<a href='https://www.caferilik.com/wp-content/uploads/2020/11/Anne-Baba-Biz-Suçluyuz-Muhafazakar-Ailelerde-Kuşak-Çatışması-Sesli-Kitap-www.caferilik.com_.mp3'>
Anne Baba Biz Suçluyuz - Muhafazakar Ailelerde Kuşak Çatışması (Sesli Kitap) www.caferilik.com<
/a></li>\n</ol>\n<p>\t</noscript><br />\n\t
<script type=\"application/json\" class=\"wp-playlist-script\">
{\"type\":\"audio\",\"tracklist\":true,\"tracknumbers\":true,\"images\":true,\"artists\":true,
\"tracks\":[{\"src\":\"https:\\/\\/www.caferilik.com\\/wp-content\\/uploads\\/2020\\/11\\/Anne-Baba-Biz-Su\\u00e7luyuz-Muhafazakar-Ailelerde-Ku\\u015fak-\\u00c7at\\u0131\\u015fmas\\u0131-Sesli-Kitap-www.caferilik.com_.mp3\",
\"type\":\"audio\\/mpeg\",\"title\":\"Anne Baba Biz Su\\u00e7luyuz - Muhafazakar Ailelerde Ku\\u015fak \\u00c7at\\u0131\\u015fmas\\u0131 (Sesli Kitap) www.caferilik.com\",\"caption\":\"\",
\"description\":\"\\\"Anne Baba Biz Su\\u00e7luyuz - Muhafazakar Ailelerde Ku\\u015fak \\u00c7at\\u0131\\u015fmas\\u0131 (Sesli Kitap) www.caferilik.com\\\".\",\"meta\":{\"length_formatted\":\"2:28:02\"},
\"image\":{\"src\":\"https:\\/\\/www.caferilik.com\\/wp-includes\\/images\\/media\\/audio.png\",\"width\":48,\"height\":64},\"thumb\":
{\"src\":\"https:\\/\\/www.caferilik.com\\/wp-includes\\/images\\/media\\/audio.png\",\"width\":48,\"height\":64}}]}</script>\n</div>\n
""";
test = test.replaceAll('\n', '').replaceAll('\t', '').replaceAll('\\', '');
Puedo encontrar muchos RegExp
para obtener link
de la cadena, pero necesito obtener la fuente detracks
Respuestas
1 RyszardCzech Nov 28 2020 at 22:42
Utilizar
"tracks":\[{"src":"([^"]+)
Ver prueba . Cuando lo pones dentro del código, el valor requerido estará en el primer grupo.
Explicación
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"tracks": '"tracks":'
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\[ '['
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{"src":" '{"src":"'
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( group and capture to \1:
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[^"]+ any character except: '"' (1 or more
times (matching the most amount
possible))
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) end of \1