Elimina il chip in react js Material-ui

Sep 20 2020

Ho lavorato con il chip react-js e Material-ui, ho aggiunto molti chip e poi un chip si presenta con il testo. Voglio avere la funzionalità per eliminare il chip. ma non riesco a cancellarlo.

come posso eliminarlo con onDelete={}?

ecco solo una parte del mio codice:

import React, { useEffect, useState, Component } from 'react'
import Chip from '@material-ui/core/Chip'

const useStyles = makeStyles(theme => ({
  root: {
    display: 'flex'
  },
  chip: {
    backgroundColor: '#104d56'
  },
}))


  const handleDelete = () => {
       console.log(hashtag);
    };

const studentlist = []

function ResponsiveDrawer(props) {
{
    namefamily.map((item, index) => {
      if (index + 1 > namefamily.length - gpcapacity) {
        if (showstu == item[2]) {
          studentlist.push(
            <Chip

              key={item[2]}
              className={classes.chip}
              clickable={false}
              variant="outlined"
              label={
                <Typography variant="caption" color="textSecondary">
                  {item[0]} {item[1]}
                </Typography>
              }
              onDelete={handele}
              icon={<FaceIcon />}
            />
          )
        } else
          studentlist.push(
            <Chip
              key={item[2]}
              variant="outlined"
              clickable={true}
              label={
                <Typography variant="caption" color="textSecondary">
                  {item[0]} {item[1]}
                </Typography>
              }

              icon={<FaceIcon />}
            />
          )
      }
    })
  }
}

cosa ci sarà all'interno di handleDelete()Function?

Risposte

1 PrasadPhule Sep 20 2020 at 19:15

Secondo la mia comprensione

  1. namefamily è un array di array cioè [['a','b','c'],['x','y','z']]
  2. vuoi saltare alcuni chip studente usando if (index + 1 > namefamily.length - gpcapacity) {condition
  3. consentire l'eliminazione dei chip per gli showstustudenti utilizzando la showstu == item[2]condizione

Ans: ResponsiveDrawerSembra che tu

vedere il mio commento nel codice per maggiori dettagli.

const ResponsiveDrawer = () => {
//considering you are getting showstu and gpcapacity as props or from somewhere

  const classes = useStyles();
  // point 2. you can skip here instead of checking if everytime
  const [chipData, setChipData] = React.useState(
     namefamily.slice(0, ((namefamily.length - 2) - gpcapacity))
   );

  const handleDelete = (chipToDelete) => {
    setChipData((chips) => chips.filter((chip) => chip[2] !== chipToDelete));
  };

  return (
       chipData.map((item, index) => {
        let chipProps = { clickable:true };
        //point 3. allowing delete to those who is {showstu}
        if (showstu == item[2]) {
          chipProps.onDelete = () => handleDelete(item[2]);
          chipProps.className = classes.chip;
          chipProps.clickable = false;
        }

        return (
          <Chip
              //for key better to use index as a unique
              key={index}
              // this is spread operator (https://reactjs.org/docs/jsx-in-depth.html#spread-attributes) 
              {...chipProps}
              variant="outlined"
              label={
                <Typography variant="caption" color="textSecondary">
                  {item[0]} {item[1]}
                </Typography>
              }
              icon={<FaceIcon />}
            />
        );
      })
  );
}