SQL Encontre pares de linhas com a próxima melhor correspondência de carimbo de data / hora

Aug 16 2020

Meu desafio é encontrar pares de linhas adjacentes por carimbo de data / hora e manter apenas os pares com distância mínima de um campo de valor (valores positivos da diferença)

Uma tabela measurementcoleta dados de diferentes sensores com um carimbo de data / hora e um valor.

id | sensor_id | timestamp | value
---+-----------+-----------+------
 1 |         1 | 12:00:00  |     5
 2 |         2 | 12:01:00  |     6
 3 |         1 | 12:02:00  |     4
 4 |         2 | 12:02:00  |     7
 5 |         2 | 12:03:00  |     3
 6 |         1 | 12:05:00  |     3
 7 |         2 | 12:06:00  |     4
 8 |         2 | 12:07:00  |     5
 9 |         1 | 12:08:00  |     6

O valor de um sensor é válido desde seu carimbo de data / hora até o carimbo de data / hora de seu próximo registro (mesmo sensor_id).

Representação gráfica

A linha verde inferior mostra a distância dos valores do sensor 1 (linha azul) e do sensor 2 (linha vermelha) ao longo do tempo.

Meu objetivo é

  1. para combinar apenas os registros de 2 sensores que correspondem à lógica do carimbo de data / hora (para obter a linha verde)
  2. para encontrar os mínimos locais dinstance em
    • 12:01:00 (às 12:00:00 não há registro para o sensor 2)
    • 12:05:00
    • 12:08:00

A tabela real reside em um banco de dados PostgreSQL e contém cerca de 5 milhões de registros de 15 sensores.

Dados de teste

create table measurement (
    id serial,
    sensor_id integer,
    timestamp timestamp,
    value integer)
;

insert into measurement (sensor_id, timestamp, value)
values
(1, '2020-08-16 12:00:00', 5),
(2, '2020-08-16 12:01:00', 6),
(1, '2020-08-16 12:02:00', 4),
(2, '2020-08-16 12:02:00', 7),
(2, '2020-08-16 12:03:00', 3),
(1, '2020-08-16 12:05:00', 3),
(2, '2020-08-16 12:06:00', 4),
(2, '2020-08-16 12:07:00', 5),
(1, '2020-08-16 12:08:00', 6)
;

Minha abordagem

era escolher 2 sensores arbitrários (por certos sensor_ids), fazer uma auto-junção e reter para qualquer registro do sensor 1 apenas aquele registro do sensor 2 com o carimbo de data / hora anterior (carimbos de data / hora maiores do sensor 2 com carimbo de data e hora do sensor 1 <= carimbo de data e hora do sensor 2) .

select
*
from (
    select
    *,
    row_number() over (partition by m1.timestamp order by m2.timestamp desc) rownum
    from measurement m1
    join measurement m2
        on m1.sensor_id <> m2.sensor_id
        and m1.timestamp >= m2.timestamp
    --arbitrarily sensor_ids 1 and 2
    where m1.sensor_id = 1
    and m2.sensor_id = 2
) foo
where rownum = 1

union --vice versa

select
*
from (
    select
    *,
    row_number() over (partition by m2.timestamp order by m1.timestamp desc) rownum
    from measurement m1
    join measurement m2
        on m1.sensor_id <> m2.sensor_id
        and m1.timestamp <= m2.timestamp
    --arbitrarily sensor_ids 1 and 2
    where m1.sensor_id = 1
    and m2.sensor_id = 2
) foo
where rownum = 1
;

Mas isso retorna um par com 12:00:00onde o sensor 2 não tem dados (não é um grande problema)
e na mesa real a execução da instrução não termina após o expediente (grande problema).

Encontrei algumas perguntas semelhantes, mas não correspondem ao meu problema

  • SQL Join no mais próximo menos que a data
  • SQL Join mesma tabela com base na data e hora e nível de inventário

Desde já, obrigado!

Respostas

2 GordonLinoff Aug 17 2020 at 00:30

A primeira etapa é calcular a diferença em cada carimbo de data / hora. Um método usa uma junção lateral e agregação condicional:

select t.timestamp,
       max(m.value) filter (where s.sensor_id = 1) as value_1,
       max(m.value) filter (where s.sensor_id = 2) as value_2,
       abs(max(m.value) filter (where s.sensor_id = 2) -
           max(m.value) filter (where s.sensor_id = 1)
          ) as diff
from (values (1), (2)) s(sensor_id) cross join
     (select distinct timestamp
      from measurement
      where sensor_id in (1, 2)
     ) t left join lateral
     (select m.value
      from measurement m 
      where m.sensor_id = s.sensor_id and
            m.timestamp <= t.timestamp
      order by m.timestamp desc
      limit 1 
     ) m
     on 1=1
group by timestamp;

Agora a questão é quando a diferença entra em um mínimo local. Para seus dados de amostra, os mínimos locais são todos de uma unidade de tempo. Isso significa que você pode usar lag()e lead()encontrá-los:

with t as (
      select  t.timestamp,
              max(m.value) filter (where s.sensor_id = 1) as value_1,
              max(m.value) filter (where s.sensor_id = 2) as value_2,
              abs(max(m.value) filter (where s.sensor_id = 2) -
                  max(m.value) filter (where s.sensor_id = 1)
                 ) as diff
      from (values (1), (2)) s(sensor_id) cross join
           (select distinct timestamp
            from measurement
            where sensor_id in (1, 2)
           ) t left join lateral
           (select m.value
            from measurement m 
            where m.sensor_id = s.sensor_id and
                  m.timestamp <= t.timestamp
            order by m.timestamp desc
            limit 1 
           ) m
           on 1=1
      group by timestamp
     )
select *
from (select t.*,
             lag(diff) over (order by timestamp) as prev_diff,
             lead(diff) over (order by timestamp) as next_diff
      from t
     ) t
where (diff < prev_diff or prev_diff is null) and
      (diff < next_diff or next_diff is null);

Essa pode não ser uma suposição razoável a se fazer. Portanto, filtre os valores duplicados adjacentes antes de aplicar esta lógica:

select *
from (select t.*,
             lag(diff) over (order by timestamp) as prev_diff,
             lead(diff) over (order by timestamp) as next_diff
      from (select t.*, lag(diff) over (order by timestamp) as test_for_dup
            from t
           ) t
      where test_for_dup is distinct from diff
     ) t
where (diff < prev_diff or prev_diff is null) and
      (diff < next_diff or next_diff is null)

Aqui está um violino db <>.

2 TheImpaler Aug 16 2020 at 16:14

Você pode usar algumas junções laterais. Por exemplo:

with
t as (select distinct timestamp as ts from measurement)
select
  t.ts, s1.value as v1, s2.value as v2,
  abs(s1.value - s2.value) as distance
from t,
lateral (
  select value
  from measurement m 
  where m.sensor_id = 1 and m.timestamp <= t.ts
  order by timestamp desc
  limit 1
) s1,
lateral (
  select value
  from measurement m 
  where m.sensor_id = 2 and m.timestamp <= t.ts
  order by timestamp desc
  limit 1
) s2
order by t.ts

Resultado:

ts                     v1  v2  distance
---------------------  --  --  --------
2020-08-16 12:01:00.0   5   6         1
2020-08-16 12:02:00.0   4   7         3
2020-08-16 12:03:00.0   4   3         1
2020-08-16 12:05:00.0   3   3         0
2020-08-16 12:06:00.0   3   4         1
2020-08-16 12:07:00.0   3   5         2
2020-08-16 12:08:00.0   6   5         1

Veja o exemplo de execução em DB Fiddle .

Além disso, se quiser todos os carimbos de data / hora , mesmo os incomparáveis 12:00:00, você pode fazer:

with
t as (select distinct timestamp as ts from measurement)
select
  t.ts, s1.value as v1, s2.value as v2,
  abs(s1.value - s2.value) as distance
from t
left join lateral (
  select value
  from measurement m 
  where m.sensor_id = 1 and m.timestamp <= t.ts
  order by timestamp desc
  limit 1
) s1 on true
left join lateral (
  select value
  from measurement m 
  where m.sensor_id = 2 and m.timestamp <= t.ts
  order by timestamp desc
  limit 1
) s2 on true
order by t.ts

Nesses casos, não é possível calcular a distância.

Resultado:

ts                     v1      v2  distance
---------------------  --  ------  --------
2020-08-16 12:00:00.0   5  <null>    <null>
2020-08-16 12:01:00.0   5       6         1
2020-08-16 12:02:00.0   4       7         3
2020-08-16 12:03:00.0   4       3         1
2020-08-16 12:05:00.0   3       3         0
2020-08-16 12:06:00.0   3       4         1
2020-08-16 12:07:00.0   3       5         2
2020-08-16 12:08:00.0   6       5         1
1 MikeOrganek Aug 16 2020 at 16:22

O preenchimento de valores ausentes requer funções de janela e um produto cartesiano de cada minuto cruzado com seus dois sensores.

O invarscte aceita os parâmetros.

with invars as (
  select '2020-08-16 12:00:00'::timestamp as start_ts,
         '2020-08-16 12:08:00'::timestamp as end_ts,
         array[1, 2] as sensor_ids
), 

Crie a matriz de minutexsensor_id

calendar as (
  select g.minute, s.sensor_id, 
         sensor_ids[1] as sid1,
         sensor_ids[2] as sid2
    from invars i
   cross join generate_series(
           i.start_ts, i.end_ts, interval '1 minute'
         ) as g(minute)
   cross join unnest(i.sensor_ids) as s(sensor_id)
),

Encontre mgrppara cada vez que um novo valor estiver disponível em umsensor_id

gaps as (
  select c.minute, c.sensor_id, m.value,
         sum(case when m.value is null then 0 else 1 end)
            over (partition by c.sensor_id 
                      order by c.minute) as mgrp,
         c.sid1, c.sid2
    from calendar c
         left join measurement m
                on m.timestamp = c.minute 
               and m.sensor_id = c.sensor_id
), 

Interpole os valores ausentes transportando o valor mais recente

interpolated as (
  select minute, 
         sensor_id,
         coalesce(
           value, first_value(value) over
                    (partition by sensor_id, mgrp
                         order by minute)
         ) as value, sid1, sid2
    from gaps
)

Faça o distancecálculo ( sum()poderia ter sido max()ou min()- não faz diferença.

select minute,
       sum(value) filter (where sensor_id = sid1) as value1,
       sum(value) filter (where sensor_id = sid2) as value2, 
       abs(
         sum(value) filter (where sensor_id = sid1) 
         - sum(value) filter (where sensor_id = sid2)
       ) as distance
  from interpolated
 group by minute
 order by minute;

Resultados:

| minute                   | value1 | value2 | distance |
| ------------------------ | ------ | ------ | -------- |
| 2020-08-16T12:00:00.000Z | 5      |        |          |
| 2020-08-16T12:01:00.000Z | 5      | 6      | 1        |
| 2020-08-16T12:02:00.000Z | 4      | 7      | 3        |
| 2020-08-16T12:03:00.000Z | 4      | 3      | 1        |
| 2020-08-16T12:04:00.000Z | 4      | 3      | 1        |
| 2020-08-16T12:05:00.000Z | 3      | 3      | 0        |
| 2020-08-16T12:06:00.000Z | 3      | 4      | 1        |
| 2020-08-16T12:07:00.000Z | 3      | 5      | 2        |
| 2020-08-16T12:08:00.000Z | 6      | 5      | 1        |

---

[View on DB Fiddle](https://www.db-fiddle.com/f/p65hiAFVT4v3TrjTPbrZnC/0)

Por favor, veja este violino funcionando .

1 wildplasser Aug 16 2020 at 16:40

Funções de janela e verificação dos vizinhos. (você precisará de um anti-selfjoin extra para remover as duplicatas e inventar um desempate para o problema de casamento estável )


SELECT id,sensor_id, ztimestamp,value
        -- , prev_ts, next_ts
        , (ztimestamp - prev_ts) AS prev_span
        , (next_ts - ztimestamp) AS next_span
        , (sensor_id <> prev_sensor) AS prev_valid
        , (sensor_id <> next_sensor) AS next_valid
        , CASE WHEN (sensor_id <> prev_sensor AND sensor_id <> next_sensor) THEN
                CASE WHEN (ztimestamp - prev_ts) < (next_ts - ztimestamp) THEN prev_id ELSE next_id END
        WHEN (sensor_id <> prev_sensor) THEN prev_id
        WHEN (sensor_id <> next_sensor) THEN next_id
        ELSE NULL END AS best_neigbor
 FROM (
        SELECT id,sensor_id, ztimestamp,value
        , lag(id) OVER www AS prev_id
        , lead(id) OVER www AS next_id
        , lag(sensor_id) OVER www AS prev_sensor
        , lead(sensor_id) OVER www AS next_sensor
        , lag(ztimestamp) OVER www AS prev_ts
        , lead(ztimestamp) OVER www AS next_ts
        FROM measurement
        WINDOW www AS (order by ztimestamp)
        ) q
ORDER BY ztimestamp,sensor_id
        ;

Resultado:


DROP SCHEMA
CREATE SCHEMA
SET
CREATE TABLE
INSERT 0 9
 id | sensor_id |     ztimestamp      | value | prev_span | next_span | prev_valid | next_valid | best_neigbor 
----+-----------+---------------------+-------+-----------+-----------+------------+------------+--------------
  1 |         1 | 2020-08-16 12:00:00 |     5 |           | 00:01:00  |            | t          |            2
  2 |         2 | 2020-08-16 12:01:00 |     6 | 00:01:00  | 00:01:00  | t          | t          |            3
  3 |         1 | 2020-08-16 12:02:00 |     4 | 00:01:00  | 00:00:00  | t          | t          |            4
  4 |         2 | 2020-08-16 12:02:00 |     7 | 00:00:00  | 00:01:00  | t          | f          |            3
  5 |         2 | 2020-08-16 12:03:00 |     3 | 00:01:00  | 00:02:00  | f          | t          |            6
  6 |         1 | 2020-08-16 12:05:00 |     3 | 00:02:00  | 00:01:00  | t          | t          |            7
  7 |         2 | 2020-08-16 12:06:00 |     4 | 00:01:00  | 00:01:00  | t          | f          |            6
  8 |         2 | 2020-08-16 12:07:00 |     5 | 00:01:00  | 00:01:00  | f          | t          |            9
  9 |         1 | 2020-08-16 12:08:00 |     6 | 00:01:00  |           | t          |            |            8
(9 rows)