Python kullanarak matematik karışım problemini çözme

Karışımlar için bir matematik problemiyle karşılaştım ve çözümü Python ve grafikler kullanarak nasıl açıklayacağımı düşünüyordum. Problem şu:

Size 20 galon yağ ve su karışımı ağırlığında bir tank verilir. Yağ yüzdesi %40'tır. Bileşimi %25 yağa seyreltmek için su eklenir.
a) Seyreltilmiş karışımın toplam ağırlığı nedir?
b) Ne kadar su eklendi?

Problemi çözmek için önce bilinenleri yazalım.

import numpy as np
import matplotlib.pyplot as plt

orig_mix_weight = 20       # 20 gallons of original mixture
orig_mix_oil_per = 0.4     # percentage of oil in the original mixture
diluted_mix_oil_per = 0.25 # percentage of oil in the diluted mixture

# percentage of water in the original mixture
orig_mix_water_per = 1 - orig_mix_oil_per
orig_mix_water_per
0.6

water, oil = 10, 9  # Assume 10 represents water and 9 oil in the matrix

# create an array with water and oil as elements in the proportion
orig_mix = np.random.choice([water, oil],
                           size=(orig_mix_weight,),
                           p=[orig_mix_water_per, orig_mix_oil_per]) # probability
orig_mix = orig_mix.reshape(5, 4) # make it a 5x4 matrix for visualization
orig_mix

      
                

                    
                    
                
            

[m,n] = np.shape(orig_mix)

plt.figure()
plt.imshow(orig_mix, alpha=0.8, cmap='Reds')
plt.xticks(np.arange(n))
plt.yticks(np.arange(m))
plt.title('Original Solution')
plt.show()

      
                

                    
                    
                
            

orig_mix_oil_weight = orig_mix_weight * orig_mix_oil_per
orig_mix_oil_weight # weight of oil in original mixture
8.0
diluted_mix_oil_weight = orig_mix_oil_weight
diluted_mix_oil_weight # weight of oil in diluted mixture
8.0

diluted_mix_alcohol_per = 0.25
diluted_mix_weight = 1 / diluted_mix_oil_per * diluted_mix_oil_weight
diluted_mix_weight
32.0

diluted_mix_water_per = 1- diluted_mix_alcohol_per

diluted_mix = np.random.choice([water, oil],
                           size=(int(diluted_mix_weight),),
                               p=[diluted_mix_water_per, diluted_mix_alcohol_per])
diluted_mix = diluted_mix.reshape(8, 4) # make it a 5x4 matrix for visualization

[m,n] = np.shape(diluted_mix)

plt.figure()
plt.imshow(diluted_mix, alpha=0.8, cmap='Reds')
plt.xticks(np.arange(n))
plt.yticks(np.arange(m))
plt.title('Diluted Solution')
plt.show()

      
                

                    
                    
                
            

diluted_mix_weight - orig_mix_weight
12.0