Dart obtient un élément de pistes à partir de String à l'aide de RegExp

Nov 28 2020

lorsque je récupère des données de l'url de notre site Web, qui renvoient cette sortie dans l'un des champs api restants et que j'essaie de trouver si elle tracksest contenue, j'obtiens l'URL de celle qui, dans cette trackssource ci-dessous, est que je dois obtenir

String test = """
<div class=\"wp-playlist wp-audio-playlist wp-playlist-light\">\n
<div class=\"wp-playlist-current-item\"></div>\n
<p>\t\t<audio controls=\"controls\" preload=\"none\" width=\"\n\t\t\t\t1118\t\"\n\t\t>
</audio></p>\n<div class=\"wp-playlist-next\"></div>\n<div class=\"wp-playlist-prev\">
</div>\n<p>\t<noscript></p>\n<ol>\n<li>
<a href='https://www.caferilik.com/wp-content/uploads/2020/11/Anne-Baba-Biz-Suçluyuz-Muhafazakar-Ailelerde-Kuşak-Çatışması-Sesli-Kitap-www.caferilik.com_.mp3'>
Anne Baba Biz Suçluyuz - Muhafazakar Ailelerde Kuşak Çatışması (Sesli Kitap) www.caferilik.com<
/a></li>\n</ol>\n<p>\t</noscript><br />\n\t
<script type=\"application/json\" class=\"wp-playlist-script\">
{\"type\":\"audio\",\"tracklist\":true,\"tracknumbers\":true,\"images\":true,\"artists\":true,
\"tracks\":[{\"src\":\"https:\\/\\/www.caferilik.com\\/wp-content\\/uploads\\/2020\\/11\\/Anne-Baba-Biz-Su\\u00e7luyuz-Muhafazakar-Ailelerde-Ku\\u015fak-\\u00c7at\\u0131\\u015fmas\\u0131-Sesli-Kitap-www.caferilik.com_.mp3\",
\"type\":\"audio\\/mpeg\",\"title\":\"Anne Baba Biz Su\\u00e7luyuz - Muhafazakar Ailelerde Ku\\u015fak \\u00c7at\\u0131\\u015fmas\\u0131 (Sesli Kitap) www.caferilik.com\",\"caption\":\"\",
\"description\":\"\\\"Anne Baba Biz Su\\u00e7luyuz - Muhafazakar Ailelerde Ku\\u015fak \\u00c7at\\u0131\\u015fmas\\u0131 (Sesli Kitap) www.caferilik.com\\\".\",\"meta\":{\"length_formatted\":\"2:28:02\"},
\"image\":{\"src\":\"https:\\/\\/www.caferilik.com\\/wp-includes\\/images\\/media\\/audio.png\",\"width\":48,\"height\":64},\"thumb\":
{\"src\":\"https:\\/\\/www.caferilik.com\\/wp-includes\\/images\\/media\\/audio.png\",\"width\":48,\"height\":64}}]}</script>\n</div>\n
""";

test = test.replaceAll('\n', '').replaceAll('\t', '').replaceAll('\\', '');

je peux en trouver beaucoup RegExpà linkpartir de la chaîne mais j'ai besoin d'obtenir la source detracks

Réponses

1 RyszardCzech Nov 28 2020 at 22:42

Utilisation

"tracks":\[{"src":"([^"]+)

Voir la preuve . Lorsque vous le mettez dans le code, la valeur requise sera dans le premier groupe.

Explication

--------------------------------------------------------------------------------
  "tracks":                '"tracks":'
--------------------------------------------------------------------------------
  \[                       '['
--------------------------------------------------------------------------------
  {"src":"                 '{"src":"'
--------------------------------------------------------------------------------
  (                        group and capture to \1:
--------------------------------------------------------------------------------
    [^"]+                    any character except: '"' (1 or more
                             times (matching the most amount
                             possible))
--------------------------------------------------------------------------------
  )                        end of \1