Dart obtient un élément de pistes à partir de String à l'aide de RegExp
Nov 28 2020
lorsque je récupère des données de l'url de notre site Web, qui renvoient cette sortie dans l'un des champs api restants et que j'essaie de trouver si elle tracks
est contenue, j'obtiens l'URL de celle qui, dans cette tracks
source ci-dessous, est que je dois obtenir
String test = """
<div class=\"wp-playlist wp-audio-playlist wp-playlist-light\">\n
<div class=\"wp-playlist-current-item\"></div>\n
<p>\t\t<audio controls=\"controls\" preload=\"none\" width=\"\n\t\t\t\t1118\t\"\n\t\t>
</audio></p>\n<div class=\"wp-playlist-next\"></div>\n<div class=\"wp-playlist-prev\">
</div>\n<p>\t<noscript></p>\n<ol>\n<li>
<a href='https://www.caferilik.com/wp-content/uploads/2020/11/Anne-Baba-Biz-Suçluyuz-Muhafazakar-Ailelerde-Kuşak-Çatışması-Sesli-Kitap-www.caferilik.com_.mp3'>
Anne Baba Biz Suçluyuz - Muhafazakar Ailelerde Kuşak Çatışması (Sesli Kitap) www.caferilik.com<
/a></li>\n</ol>\n<p>\t</noscript><br />\n\t
<script type=\"application/json\" class=\"wp-playlist-script\">
{\"type\":\"audio\",\"tracklist\":true,\"tracknumbers\":true,\"images\":true,\"artists\":true,
\"tracks\":[{\"src\":\"https:\\/\\/www.caferilik.com\\/wp-content\\/uploads\\/2020\\/11\\/Anne-Baba-Biz-Su\\u00e7luyuz-Muhafazakar-Ailelerde-Ku\\u015fak-\\u00c7at\\u0131\\u015fmas\\u0131-Sesli-Kitap-www.caferilik.com_.mp3\",
\"type\":\"audio\\/mpeg\",\"title\":\"Anne Baba Biz Su\\u00e7luyuz - Muhafazakar Ailelerde Ku\\u015fak \\u00c7at\\u0131\\u015fmas\\u0131 (Sesli Kitap) www.caferilik.com\",\"caption\":\"\",
\"description\":\"\\\"Anne Baba Biz Su\\u00e7luyuz - Muhafazakar Ailelerde Ku\\u015fak \\u00c7at\\u0131\\u015fmas\\u0131 (Sesli Kitap) www.caferilik.com\\\".\",\"meta\":{\"length_formatted\":\"2:28:02\"},
\"image\":{\"src\":\"https:\\/\\/www.caferilik.com\\/wp-includes\\/images\\/media\\/audio.png\",\"width\":48,\"height\":64},\"thumb\":
{\"src\":\"https:\\/\\/www.caferilik.com\\/wp-includes\\/images\\/media\\/audio.png\",\"width\":48,\"height\":64}}]}</script>\n</div>\n
""";
test = test.replaceAll('\n', '').replaceAll('\t', '').replaceAll('\\', '');
je peux en trouver beaucoup RegExp
à link
partir de la chaîne mais j'ai besoin d'obtenir la source detracks
Réponses
1 RyszardCzech Nov 28 2020 at 22:42
Utilisation
"tracks":\[{"src":"([^"]+)
Voir la preuve . Lorsque vous le mettez dans le code, la valeur requise sera dans le premier groupe.
Explication
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"tracks": '"tracks":'
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\[ '['
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{"src":" '{"src":"'
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( group and capture to \1:
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[^"]+ any character except: '"' (1 or more
times (matching the most amount
possible))
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) end of \1